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Question

Physics Question on Current electricity

Three resistances of equal values are arranged in four different configurations as shown below. Power dissipation in the increasing order is

A

(III)<(II)<(IV)<(I)( III ) < ( II ) < ( IV ) < ( I )

B

(II)<(III)<(IV)<(I)( II ) < ( III ) < ( IV ) < ( I )

C

(I)<(IV)<(III)<(II)(I) < ( IV ) < ( III ) < ( II )

D

(I)<(III)<(II)<(IV)( I ) < ( III ) < ( II ) < ( IV )

Answer

(III)<(II)<(IV)<(I)( III ) < ( II ) < ( IV ) < ( I )

Explanation

Solution

For figure I, Total resistance =3R=3 R I power =I2(3R)=I^{2}(3 R)
For figure II, Resistance =2R3Ω=\frac{2 R}{3} \Omega II power =I2(2R3)=I^{2}\left(\frac{2 R}{3}\right)
For figure III, Total resistance =R3Ω=\frac{R}{3} \Omega III power =I2(R3)=I^{2}\left(\frac{R}{3}\right)
For figure IV, Total resistance 32Ω\frac{3}{2} \Omega IV power =I2(32R)=I^{2}\left(\frac{3}{2} R\right)