Question

Three resistances each of $4\, \Omega$ are connected to form a triangle. The resistance between any two terminals is

• A. $12\, \Omega$
• B. $2\, \Omega$
• C. $6\, \Omega$
• D. $8/3\, \Omega$

Answer 1

Answer: (D)

$8/3\, \Omega$

Answer 2

The two resistances are connected in series and the resultant is connected in parallel with the third resistance.
$\therefore \, \, R= 4\, \Omega+4\, \Omega=8\, \Omega$ and $\frac{1}{R''}=\frac{1}{8}+\frac{1}{4} =\frac{3}{8}$
or $R''=\frac{8}{3} \Omega$