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Question: Three resistances, each of 1 ohm, are joined in parallel. Three such combinations are put in series,...

Three resistances, each of 1 ohm, are joined in parallel. Three such combinations are put in series, then the resultant resistance will be

A

9 ohm

B

3 ohm

C

1 ohm

D

13ohm\frac{1}{3}ohm

Answer

1 ohm

Explanation

Solution

1R=11+11+11=31\frac{1}{R} = \frac{1}{1} + \frac{1}{1} + \frac{1}{1} = \frac{3}{1}R=13ohmR = \frac{1}{3}ohm

Now such three resistance are joined in series, hence total R=13+13+13=1ohmR = \frac{1}{3} + \frac{1}{3} + \frac{1}{3} = 1ohm