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Question

Mathematics Question on Sequence and series

Three positive numbers form an increasing G.P.G.P. If the middle term in this G.P.G.P. is doubled, then new numbers are in A.P.A.P. Then, the common ratio of the G.P.G.P. is

A

2+3\sqrt 2 + \sqrt 3

B

3+2 3 + \sqrt 2

C

232 - \sqrt 3

D

2+32 + \sqrt 3

Answer

2+32 + \sqrt 3

Explanation

Solution

a,ar,ar2G.P.a, a r, a r^{2} \rightarrow G.P.
a,2ar,ar2A.P.a, 2 a r, a r^{2} \rightarrow A.P.
2×2ar=a+ar22 \times 2 a r=a+a r^{2}
4r=1+r24 r=1+r^{2}
r24r+1=0\Rightarrow r^{2}-4 r+1=0
r=4±1642=2±3r=\frac{4 \pm \sqrt{16-4}}{2}=2 \pm \sqrt{3}
r=2+3r=2+\sqrt{3}
r=23r=2-\sqrt{3} is rejected
(r>1)\because (r>\,1)
G.P. is increasing.