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Question

Physics Question on Polarisation

Three polaroid sheets P1,P2P_1, P_2 and P3P_3 are kept parallel to each other such that the angle between pass axes of P1P_1 and P2P_2 is 4545^\circ and that between P2P_2 and P3P_3 is 4545^\circ. If unpolarised beam of light of intensity 128Wm2128 Wm^{-2} is incident on P1P_1. What is the intensity of light coming out of P3P_3?

A

128Wm2128 \,Wm^{-2}

B

0

C

16Wm216 \,Wm^{-2}

D

64Wm264\, Wm^{-2}

Answer

16Wm216 \,Wm^{-2}

Explanation

Solution

We have unpolarised beam's intensity
I0=128w/m2I _{0}=128 w / m ^{2}
Using Malu's law we have
I=I0cos2θI=I_{0} \cos ^{2} \theta
When beam passed from the first polaroid,
I=I0/2I=I_{0} / 2
Again, as the angle between p1p _{1} and p2p _{2} is 4545^{\circ},
beam intensity when it will pass p2p _{2} would be
l1=I0/2cos2450=I0/4l _{1}= I _{0} / 2 \cos ^{2} 45^{0}= I _{0} / 4
And, also the angle between p2p _{2} and p3p _{3} is 4545^{\circ},
beam intensity when it will come out of p3p _{3} will be
l2=I0/4cos2450=I0/8l _{2}=I_{0} / 4 \cos ^{2} 45^{0}=I_{0} / 8
=128/8=16w/m2=128 / 8=16 w / m ^{2}