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Physics Question on Electric Charge

Three point charges of magnitude 55 μCμC, 0.16μC0.16μC and 0.3μC0.3μC are located at the vertices, B,CB, C of a right angled triangle whose sides are AB=3AB = 3 cm, BC=32BC = 3\sqrt2 cm and CA=3CA = 3 cm and point A is the right angle corner. Charge at point A, experiences ______N of electrostatic force due to the other two charges.

Answer

FAC=k(5×0.3)×10−129×10−4F_{AC} = \frac{k(5 \times 0.3) \times 10^{-12}}{9 \times 10^{-4}}

FAB=k(5×0.16)×10−129×10−4F_{AB} = \frac{k(5 \times 0.16)\times 10^{-12}}{9\times 10^{-4}}

Fnet=k×10−129×10−41.52+(0.8)2F_{net} = \frac{k \times 10^{-12}}{9\times 10^{-4}} \sqrt{1.5^2+(0.8)^2}

= 109×10−1210−4×1.7\frac{10^9 \times 10^{-12}}{10^{-4} \times 1.7}

= 1717