Question
Question: Three particles start moving simultaneously from a point on a horizontal smooth plane. First particl...
Three particles start moving simultaneously from a point on a horizontal smooth plane. First particle moves with speed v1 towards east, second particle moves towards north with speed v2 and third one moves towards north east. The velocity of the third particle, so that the three always lie on a straight line, is
A
2v1+v2
B
v1v2s
C
v1+v2v1v2
D
2v1+v2v1v2
Answer
2v1+v2v1v2
Explanation
Solution
using x2−x1y2−y1=x1−x3y1−y3, we have
0−v1tv2t−0=v1t−(v3/2)t0−(v3/2)t
⇒ v3 = v1+v22v1v2,
Hence (4) is correct.