Question

Three particles, each having a charge of 10μC are placed at the corners of an equilateral triangle of side 10cm. The electrostatic potential energy of the system is (Given $\frac{1}{4\pi\varepsilon_{0}} = 9 \times 10^{9}N - m^{2} ⥂ / ⥂ C^{2})$

• A. Zero
• B. Infinite
• C. 27 J
• D. 100 J

Answer 1

Answer: (C)

27 J

Answer 2

Potential energy of the system,

$U = 9 \times 10^{9}\left\lbrack \frac{(10 \times 10^{- 6})^{2}}{0.1} \times 3 \right\rbrack$ = 27 J