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Data Interpretation & Logical Reasoning (DILR) Question on Table

Three participants – Akhil, Bimal and Chatur participate in a random draw competition for five days. Every day, each participant randomly picks up a ball numbered between 1 and 9. The number on the ball determines his score on that day. The total score of a participant is the sum of his scores attained in the five days. The total score of a day is the sum of participants’ scores on that day. The 2-day average on a day, except on Day 1, is the average of the total scores of that day and of the previous day. For example, if the total scores of Day 1 and Day 2 are 25 and 20, then the 2-day average on Day 2 is calculated as 22.5. Table 1 gives the 2-day averages for Days 2 through 5.Table 1: 2-day averages for Days through 5

Day 2| Day 3| Day 4| Day 5
15| 15.5| 16| 17
Participants are ranked each day, with the person having the maximum score being awarded the minimum rank (1) on that day. If there is a tie, all participants with the tied score are awarded the best available rank. For example, if on a day Akhil, Bimal, and Chatur score 8, 7 and 7 respectively, then their ranks will be 1, 2 and 2 respectively on that day. These ranks are given in Table 2. Table 2 : Ranks of participants on each day

| Day 1| Day 2| Day 3| Day 4| Day 5
Akhil| 1| 2| 2| 3| 3
Bimal| 2| 3| 2| 1| 1
Chatur| 3| 1| 1| 2| 2
The following information is also known.
1. Chatur always scores in multiples of 3. His score on Day 2 is the unique highest score in the competition. His minimum score is observed only on Day 1, and it matches Akhil’s score on Day 4.
2. The total score on Day 3 is the same as the total score on Day 4.
3. Bimal’s scores are the same on Day 1 and Day 3.
What is the minimum possible total score of Bimal? (This Question was asked as TITA)

A

27

B

25

C

20

D

23

Answer

25

Explanation

Solution

The value of a can be 45\frac{4}{5}, and the value of b can be 21\frac{2}{1}.

Let's consider this following table:

| Day 1| Day 2| Day 3| Day 4| Day 5| Total Score
---|---|---|---|---|---|---
Akhil| 7| 4b\frac{4}{b}| b| 3| 34\frac{3}{4}| 23/24/25
Bimal| 5| 21\frac{2}{1}| 5| 7| 78\frac{7}{8}| 27/26/25
Chatur| 3| 9| 6| 6| 6| 30
Total Score| 15| 15| 16| 16| 18| 80

From the table, we can see that the minimum possible total score of Bimal will be 25.

So, the correct option is (B): 25.