Question

Three numbers are in A.P. whose sum s 33 and product is 792, then the smallest number from these numbers is.

• A. 4
• B. 8
• C. 11
• D. 14

Answer 1

Answer: (A)

4

Answer 2

Suppose that three numbers are $a + d , a , a - d$

Therefore $a + d + a + a - d = 33$ $\Rightarrow$ $a = 11$

$a ( a + d ) ( a - d ) = 792$ $\Rightarrow$ $11 \left( 121 - d ^ { 2 } \right) = 792$ $\Rightarrow$ $d = 7$

Then required numbers are 4, 11, 18.

Hence smallest number is 4.