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Question

Physics Question on Gravitational Potential Energy

Three masses m,2mm,\, 2\, m and 3m3\, m are arranged in two triangular configurations as shown in figure 11 and figure 22 . Work done by an external agent in changing, the configuration from figure 11 to figure 22 is

A

6Gm2a[262]\frac{6Gm^{2}}{a}\left[2-\frac{6}{\sqrt{2}}\right]

B

0

C

Gm2a[6+62] - \frac{Gm^{2}}{a}\left[ 6 + \frac{6}{\sqrt{2}}\right]

D

Gm2a[662] - \frac{Gm^{2}}{a}\left[6-\frac{6}{\sqrt{2}}\right]

Answer

Gm2a[662] - \frac{Gm^{2}}{a}\left[6-\frac{6}{\sqrt{2}}\right]

Explanation

Solution

Work done to change configuration from 1 to 2 can be calculated by
W12=(UfUi)W_{12}=-\left(U_{f}-U_{i}\right)
=[Gm2a(2+3+62)(Gm2a(2+3+6))]=-\left[-\frac{G m^{2}}{a}\left(2+3+\frac{6}{\sqrt{2}}\right)-\left(-\frac{G m^{2}}{a}(2+3+6)\right)\right]
=Gm2a(662)=-\frac{G m^{2}}{a}\left(6-\frac{6}{\sqrt{2}}\right)