Question

Three masses are connected (as Shown) on a horizontal frictionless surface and pulled by a force of 60 N. The tensions ${{T}_{1}}$ and ${{T}_{2}}$ are in the ratio

• A. $1:1$
• B. $1:5$
• C. $1:4$
• D. $4:5$

Answer 1

Answer: (B)

$1:5$

Answer 2

: Horizontal component of force $=60\text{ }cos30{}^\circ$ $=30N$ Acceleration of system $a=\frac{force}{(3+12+15)}$ $=\frac{30}{30}=1\,m/{{s}^{2}}$ $\therefore$ ${{T}_{2}}=$ mass pulled x acceleration $=(3+12)\times 1=15N$ ${{T}_{1}}=3\times 1=3N$ $\therefore$ $\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{3}{15}=\frac{1}{5}$