Question

Three inductances are connected as shown below. Assuming no coupling, the resultant inductance will be

• A. 0.25 H
• B. 0.75 H
• C. 0.01 H
• D. 1H

Answer 1

Answer: (D)

1H

Answer 2

L₂ and L₃ are in parallel. Thus their combination gives $L' = \frac{L_{2}L_{3}}{L_{2} + L_{3}} = 0.25H$

The L′ and L₁ are in series, thus the equivalent inductance is L = L₁ + L′ = 0.75 + 0.25 = 1H.