Question

Three identical particle $A, B$ and$C$ of mass $100 \,kg$ each are placed in a straight line with $AB = BC =13 \,m$ The gravitational force on a fourth particle $P$ of the same mass is $F$, when placed at a distance $13\, m$ from the particle B on the perpendicular bisector of the line $AC$ The value of $F$ will be approximately :

• A. 21 G
• B. 100 G
• C. 59 G
• D. 42 G

Answer 1

Answer: (B)

100 G

Answer 2

The correct option is (B)