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Question: Three identical blocks A, B and C are placed on horizontal frictionless surface. The blocks B and C ...

Three identical blocks A, B and C are placed on horizontal frictionless surface. The blocks B and C are at rest. But A is approaching towards B with a speed 10 m/s. The coefficient of restitution for all collisions is 0.5. The speed of the block C just after collision is :

A

5.6 m/s

B

6 m/s

C

8 m/s

D

10 m/s

Answer

5.6 m/s

Explanation

Solution

\ vB = m1(1+e)m1+m2\frac{m_{1}(1 + e)}{m_{1} + m_{2}} u1 = m(1+0.5)m+m\frac{m(1 + 0.5)}{m + m} (10) = 7.5 m/s

vc = m(1+0.5)m+m\frac{m(1 + 0.5)}{m + m} (7.5) = 5.6 m/s