Question

Three houses are available in a locality. Three person apply for house. Each applies for one house without consulting others. The probability that all the three apply for same house

• A. 8/9
• B. 7/9
• C. 2/9
• D. 1/9

Answer 1

Answer: (D)

1/9

Answer 2

One can apply by '3' ways

So total cases = 3³ = 27 Favourable cases that they all apply for one is =3

P = $\frac { 3 } { 27 }$ = $\frac { 1 } { 9 }$