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Question

Quantitative Aptitude Question on Probability

Three groups A, B and C are contesting for position on the Board of Directors of a company. The probabilities of their winning are 0.5, 0.3 and 0.2 respectively. If the group A wins the probability of introducing a new position is 0.7 and the corresponding probabilities for group B and C are 0.6 and 0.5 respectively. The probability that a new position introduced is

A

0.52

B

0.63

C

0.74

D

None of the above

Answer

0.63

Explanation

Solution

To find the probability that a new position is introduced, you need to calculate the weighted average of the probabilities based on each group's probability of winning.
Let P(new position introduced) be the probability that a new position is introduced. Then, you can calculate it as follows:
P(new position introduced) = P(A wins)×\timesP(new position introduced by A)++P(B wins)×\timesP(new position introduced by B)++P(C wins)×\timesP(new position introduced by C)
P(new position introduced) = (0.5×\times0.7)++(0.3×\times0.6)++(0.2×\times0.5)
P(new position introduced) = 0.35++0.18++0.1
P(new position introduced) = 0.63
So, the correct answer is (2) 0.63.