Question
Quantitative Aptitude Question on Probability
Three groups A, B and C are contesting for position on the Board of Directors of a company. The probabilities of their winning are 0.5, 0.3 and 0.2 respectively. If the group A wins the probability of introducing a new position is 0.7 and the corresponding probabilities for group B and C are 0.6 and 0.5 respectively. The probability that a new position introduced is
0.52
0.63
0.74
None of the above
0.63
Solution
To find the probability that a new position is introduced, you need to calculate the weighted average of the probabilities based on each group's probability of winning.
Let P(new position introduced) be the probability that a new position is introduced. Then, you can calculate it as follows:
P(new position introduced) = P(A wins)×P(new position introduced by A)+P(B wins)×P(new position introduced by B)+P(C wins)×P(new position introduced by C)
P(new position introduced) = (0.5×0.7)+(0.3×0.6)+(0.2×0.5)
P(new position introduced) = 0.35+0.18+0.1
P(new position introduced) = 0.63
So, the correct answer is (2) 0.63.