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Question: Three forces of magnitudes 6 N, 6 N and \(\sqrt { 72 }\)N act at corner of cube along three sides as...

Three forces of magnitudes 6 N, 6 N and 72\sqrt { 72 }N act at corner of cube along three sides as shown in figure. Resltant of these forces is

A

12 N angle OB

B

18 N along OA

C

18 N along OC

D

12 N along OE

Answer

12 N along OE

Explanation

Solution

Resultant of these forces is

R=(6)2+(6)2+(72)2R = \sqrt { ( 6 ) ^ { 2 } + ( 6 ) ^ { 2 } + \sqrt { ( 72 ) ^ { 2 } } } along OE

=36+36+72=12 N= \sqrt { 36 + 36 + 72 } = 12 \mathrm {~N}along OE