Question
Question: Three forces \(\mathbf{i} + 2\mathbf{j} - 3\mathbf{k},2\mathbf{i} + 3\mathbf{j} + 4\mathbf{k}\) and ...
Three forces i+2j−3k,2i+3j+4k and i−j+k are acting on a particle at the point (0, 1, 2). The magnitude of the moment of the forces about the point (1, – 2, 0) is
A
31(p+q+r)
B
610
C
417
D
None of these
Answer
610
Explanation
Solution
Total force
F→=(i+2j−3k)+(2i+3j+4k)+(i−j+k)=4i+4j+2kMoment of the forces about P = r×F→=PA→×F→
PA→=(0−1)i+(1+2)j+(2−0)k=−i+3j+2k
∴ Moment about P = (−i+3j+2k)×(4i+4j+2k)
=$\left| \begin{matrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \
- 1 & 3 & 2 \ 4 & 4 & 2 \end{matrix} \right| = - 2\mathbf{i} + 10\mathbf{j} - 16\mathbf{k}$
Magnitude of the moment = ∣−2i+10j−16k∣
= 212+52+82=290=610
