Three fair dice are rolled simultaneously. Let a, b, c be th... | Mathematics | SolveeIt | Solveeit

Today, August 23

Question

Three fair dice are rolled simultaneously. Let a, b, c be the numbers on the top of the dice. Then the probability that min(a, b, c) =6 is

A

$\frac{1}{216}$

B

$\frac{1}{36}$

C

$\frac{1}{6}$

D

$\frac{11}{216}$

E

$\frac{5}{6}$

Answer

$\frac{1}{216}$

Explanation

Solution

The correct option is (A) : $\frac{1}{216}$