Question

Three fair coins are tossed. If both heads and tails appears, then the probability that exactly one head appears, is

• A. $\frac { 3 } { 8 }$
• B. $\frac { 1 } { 6 }$
• C. $\frac { 1 } { 2 }$
• D. $\frac { 1 } { 3 }$

Answer 1

Answer: (C)

$\frac { 1 } { 2 }$

Answer 2

Since both heads and tails appears, so

$n ( S ) = \{ H H T , H T H , T H H , H T T , T H T , T T H \}$

$n ( E ) = \{ H T T , T H T , T T H \}$

Hence required probability