Question

Three faces of a fair dice are yellow, two faces red and only one is blue. The dice is tossed three times. The probability that the colour yellow, red and blue appears in the first, second and the third tosses respectively is:

• A. $\frac{1}{30}$
• B. $\frac{1}{25}$
• C. $\frac{1}{36}$
• D. $\frac{1}{32}$

Answer 1

Answer: (C)

$\frac{1}{36}$

Answer 2

Given that three faces of fair dice are yellow, two faces are red and only one is blue. $\therefore$ P (yellow) $= \frac{3}{6}$, P(red) = $\frac{2}{6}, = \frac{1}{6}$ and P (blue) $\therefore$ P (yellow, red and blue) = P (yellow) $\times$ P (red) $\times$ P (blue) $= \frac{3}{6} \times \frac{2}{6} \times \frac{1}{6} = \frac{1}{36}$