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Question

Physics Question on Current electricity

Three equal resistors connected in series across a source of e.m.f. together dissipate 10 watt of power. What will be the power dissipated in watt if the same resistors are connected in parallel across the same source of e.m.f. ?

A

30

B

103\frac{10}{3}

C

10

D

90

Answer

90

Explanation

Solution

For series, Req=3rR_{eq}=3r
Power =V23r=10V2r=30.=\frac{V^2}{3r}= 10 \Rightarrow \frac{V^2}{r}=30.
For parallel Req=r/3R_{eq}=r/3
Power =V2r/3=3V2r=3×30=90watt.=\frac{V^2}{r/3}= \frac{3V^2}{r} = 3 \times 30 = 90\, watt.