Solveeit Logo

Question

Question: Three equal charges each +*Q*, placed at the corners of on equilateral triangle of side a what will ...

Three equal charges each +Q, placed at the corners of on equilateral triangle of side a what will be the force on any charge (k=14πε0)\left( k = \frac{1}{4\pi\varepsilon_{0}} \right)

A

kQ2a2\frac{kQ^{2}}{a^{2}}

B

2kQ2a2\frac{2kQ^{2}}{a^{2}}

C

2kQ2a2\frac{\sqrt{2}kQ^{2}}{a^{2}}

D

3kQ2a2\frac{\sqrt{3}kQ^{2}}{a^{2}}

Answer

3kQ2a2\frac{\sqrt{3}kQ^{2}}{a^{2}}

Explanation

Solution

Suppose net force is to be calculated on the charge which is kept at A. Two charges kept at B and C are applying force on that particular charge, with direction as shown in the figure.

Since Fb=Fc=F=kQ2a2F_{b} = F_{c} = F = k\frac{Q^{2}}{a^{2}}

So, Fnet=FB2+FC2+2FBFCcos60F_{net} = \sqrt{F_{B}^{2} + F_{C}^{2} + 2F_{B}F_{C}\cos 60}

Fnet=3F=3kQ2a2F_{net} = \sqrt{3}F = \frac{\sqrt{3}kQ^{2}}{a^{2}}