Question

Three dice are rolled once. The chance of getting a score of $5$ is

• A. $\frac{5}{216}$
• B. $\frac{1}{6}$
• C. $\frac{1}{36}$
• D. $\frac{1}{7^2}$

Answer 1

Answer: (C)

$\frac{1}{36}$

Answer 2

Total number of outcomes = $6 \times 6 \times 6$ $=216$ When sum of numbers is 5, then outcomes are $(1, 1, 3), (1, 2, 2), (1, 3, 1), (2, 1, 2), (2, 2, 1)$ and $(3, 1, 1)$. $\therefore$ Required probability = $\frac{6}{216} = \frac{1}{36}$