Question

Three copper blocks of masses M1, M2 and M3 kg respectively are brought into thermal contact till they reach equilibrium. Before contact, they were at T1, T2, T3

(T1 > T2 > T3). Assuming there is no heat loss to the surroundings, the equilibrium temperature T is (s is specific heat of copper)

• A. T =
• B. T = $\frac { \mathrm { M } _ { 1 } \mathrm {~T} _ { 1 } + \mathrm { M } _ { 2 } \mathrm {~T} _ { 2 } + \mathrm { M } _ { 3 } \mathrm {~T} _ { 3 } } { \mathrm { M } _ { 1 } + \mathrm { M } _ { 2 } + \mathrm { M } _ { 3 } }$
• C. T = $\frac { \mathrm { M } _ { 1 } \mathrm {~T} _ { 1 } + \mathrm { M } _ { 2 } \mathrm {~T} _ { 2 } + \mathrm { M } _ { 3 } \mathrm {~T} _ { 3 } } { 3 \left( \mathrm { M } _ { 1 } + \mathrm { M } _ { 2 } + \mathrm { M } _ { 3 } \right) }$
• D. T =

Answer 1

Answer: (B)

T = $\frac { \mathrm { M } _ { 1 } \mathrm {~T} _ { 1 } + \mathrm { M } _ { 2 } \mathrm {~T} _ { 2 } + \mathrm { M } _ { 3 } \mathrm {~T} _ { 3 } } { \mathrm { M } _ { 1 } + \mathrm { M } _ { 2 } + \mathrm { M } _ { 3 } }$

Answer 2