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Question: Three containers of the same volume contain three different gases. The masses of the molecules are \...

Three containers of the same volume contain three different gases. The masses of the molecules are m1,m2m_{1},m_{2} and m3m_{3} and the number of molecules in their respective containers are N1,N2N_{1},N_{2} andN3N_{3}. The gas pressure in the containers are P1,P2P_{1},P_{2} and P3P_{3} respectively. All the gases are now mixed and put in one of the containers. The pressure P of mixture will be

A

P<(P1+P2+P3)P < (P_{1} + P_{2} + P_{3})

B

P=P1+P2+P33P = \frac{P_{1} + P_{2} + P_{3}}{3}

C

P=P1+P2+P3P = P_{1} + P_{2} + P_{3}

D

P>(P1+P2+P3)P > (P_{1} + P_{2} + P_{3})

Answer

P=P1+P2+P3P = P_{1} + P_{2} + P_{3}

Explanation

Solution

According to the Dalton’s law of partial pressures, the total pressure will be P1+P2+P3.P_{1} + P_{2} + P_{3}.