Question

Three condensers each of capacitance $2F$ are put in series. The resultant capacitance is

• A. (a) $6F$
• A. (b) $\frac{3}{2}F$
• A. (c) $\frac{2}{3}F$
• A. (d) $5F$

Answer 1

(c)

Sol. $\frac{1}{C} = \frac{1}{2} + \frac{1}{2} + \frac{1}{2}$ ⇒ $C = \frac{2}{3}F$