Question

Three concurrent forces of the same magnitude are in equilibrium. What is the angle between the forces ? Also name the triangle formed by the forces as sides-

• A. $60^{0}$equilateral triangle
• B. $120^{0}$equilateral triangle
• C. $\text{12}\text{0}^{0}\text{, 3}\text{0}^{0}\text{, 3}\text{0}^{0}$an isosceles triangle
• D. $120^{0}$an obtuse angled triangle

Answer 1

Answer: (A)

$60^{0}$equilateral triangle

Answer 2

In N forces of equal magnitude works on a single point and their resultant is zero then angle between any two forces is given

$\theta = \frac{360}{N} = \frac{360}{3} = 120^{0}$

If these three vectors are represented by three sides of triangle then they form equilateral triangle