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Question: Three charges – q<sub>1</sub>, q<sub>2</sub> and – q<sub>3</sub> are placed as shown in the figure. ...

Three charges – q1, q2 and – q3 are placed as shown in the figure. The x-component of the force on –q1 is proportional to–

A

q2b2q3a2sinθ\frac{q_{2}}{b^{2}}–\frac{q_{3}}{a^{2}}\sin\theta

B

q2b2q3a2cosθ\frac{q_{2}}{b^{2}}–\frac{q_{3}}{a^{2}}\cos\theta

C

q2b2+q3a2sinθ\frac{q_{2}}{b^{2}} + \frac{q_{3}}{a^{2}}\sin\theta

D

q2b2+q3a2cosθ\frac{q_{2}}{b^{2}} + \frac{q_{3}}{a^{2}}\cos\theta

Answer

q2b2+q3a2sinθ\frac{q_{2}}{b^{2}} + \frac{q_{3}}{a^{2}}\sin\theta

Explanation

Solution

x component of force on – q Ž

F1 cos(90 – q) + F2

=