Question

Three charges $-q_1, +q_2$ and $-q_3$ are placed as shown in the figure. The x-component of the force on $-q_1$ is proportional to

• A. $\frac{q_{1}}{b^{2}}-\frac{q_{3}}{a^{2}}cos\,\theta$
• B. $\frac{q_{2}}{b^{2}}+\frac{q_{3}}{a^{2}}sin\,\theta$
• C. $\frac{q_{1}}{b^{2}}+\frac{q_{3}}{a^{2}}cos\,\theta$
• D. $\frac{q_{2}}{b^{2}}-\frac{q_{3}}{a^{2}}sin\,\theta$

Answer 1

Answer: (B)

$\frac{q_{2}}{b^{2}}+\frac{q_{3}}{a^{2}}sin\,\theta$

Answer 2

$F_{x}\propto\frac{q_{2}}{b^{2}}+\frac{q_{3}}{a^{2}}sin\,\theta$