Question

Three capacitors each of capacity $4\mu F$ are to be connected in such a way that the effective capacitance is $6\mu F$. This can be done by.

• A. (a) Connecting them in series
• A. (b) Connecting them in parallel
• A. (c) Connecting two in series and one in parallel
• A. (d) Connecting two in parallel and one in series

Answer 1

(c): To get equivalent capacitance $6\mu F,$ two $4\mu F$ capacitors are to be connected in series and third one is connected in parallel.

From figure equivalent capacitance,

$C_{eq} = \frac{4 \times 4}{4 + 4} + 4 = 2 + 4 = 6\mu F$