Question

Three capacitors each of capacitance $1\mu F$are connected in parallel. To this combination, a fourth capacitor of capacitance $1\mu F$ is connected in series. The resultant capacitance of the system is

• A. $4\mu F$
• B. $2\mu F$
• C. $\frac{4}{3}\mu F$
• D. $\frac{3}{4}\mu F$

Answer 1

Answer: (D)

$\frac{3}{4}\mu F$

Answer 2

The circuit can be drawn as follows

Sol.

$\Rightarrow C_{AB} = \frac{3 \times 1}{3 + 1} = \frac{3}{4}\mu F$