Question

Three capacitors are connected to $D.C.$ source of $100\mspace{6mu} volts$shown in the adjoining figure. If the charge accumulated on plates of $C_{1},\mspace{6mu} C_{2}$and $C_{3}$ are $q_{a},\mspace{6mu} q_{b},\mspace{6mu} q_{c},q_{d}.q_{e}$and$q_{f}$ respectively, then

• A. (a) $q_{b} + q_{d} + q_{f} = \frac{100}{9}C$
• A. (b) $q_{b} + q_{d} + q_{f} = 0$
• A. (c) $q_{a} + q_{c} + q_{e} = 50C$
• A. (d) $q_{b} = q_{d} = q_{f}$

Answer 1

(d)

Sol. In series combination, charge is same on each

capacitor.