Question

Three boys and two girls stand in a queue. The probability that the number of boys a head of every girl is atleast one more that the number of girls ahead of her, is

• A. 44563
• B. 44564
• C. 44595
• D. 44624

Answer 1

Answer: (A)

44563

Answer 2

Either a girl will start the sequence or will be at second position and will not acquire the last position as well.
Required probability $=\frac{\left({ }^{3} C _{1}+{ }^{2} C _{1}\right)}{{ }^{5} C _{2}}=\frac{1}{2}$