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Question: Three blocks of masses m<sub>1</sub>, m<sub>2</sub> and m<sub>3</sub> are placed on a horizontal fri...

Three blocks of masses m1, m2 and m3 are placed on a horizontal frictionless surface. A force of 40 N pulls the system then calculate the value of T, if m1 = 10kg, m2 = 6 kg, m3 = 4 kg –

A

40 N

B

20 N

C

10 N

D

5 N

Answer

20 N

Explanation

Solution

a = Fm1+m2+m3\frac { \mathrm { F } } { \mathrm { m } _ { 1 } + \mathrm { m } _ { 2 } + \mathrm { m } _ { 3 } } = 4010+6+4\frac { 40 } { 10 + 6 + 4 } = 2m/s2

40 – T = 10 × 2

T = 20 N