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Question: Three blocks of masses \(m _ { 1 } , m _ { 2 }\) and \(m _ { 3 }\) are connected by massless str...

Three blocks of masses m1,m2m _ { 1 } , m _ { 2 } and m3m _ { 3 } are connected by massless strings as shown on a frictionless table. They are pulled with a force T3=40 NT _ { 3 } = 40 \mathrm {~N} . If m1=10 kg,m2=6 kgm _ { 1 } = 10 \mathrm {~kg} , m _ { 2 } = 6 \mathrm {~kg} and m3=4 kgm _ { 3 } = 4 \mathrm {~kg} , the tension T2T _ { 2 } will be

A

20 N

B

40 N

C

10 N

D

32 N

Answer

32 N

Explanation

Solution

T2=(m1+m2)×T3m1+m2+m3=(10+6)×4020T _ { 2 } = \left( m _ { 1 } + m _ { 2 } \right) \times \frac { T _ { 3 } } { m _ { 1 } + m _ { 2 } + m _ { 3 } } = \frac { ( 10 + 6 ) \times 40 } { 20 } =32 N= 32 \mathrm {~N}