Question

Three blocks of masses $m_1, m_2$ and $m_3$ kg are placed in contact with each other on a frictionless table. A force $F$ is applied on the heaviest mass $m_1$; the acceleration of $m_3$ will be

• A. $\frac{F}{m_1}$
• B. $\frac{F}{m_1 + m_2}$
• C. $\frac{F}{m_2 + m_3}$
• D. $\frac{F}{m_1 + m_2 + m_3}$

Answer 1

Answer: (D)

$\frac{F}{m_1 + m_2 + m_3}$

Answer 2

The acceleration of mass $m_{3}$
$=$common acceleration of the system
$=\frac{\text { force applied }}{\text { total mass }}$
$=\frac{F}{m_{1}+m_{2}+m_{3}}$