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Question

Physics Question on tension

Three blocks of masses 2kg,3kg2\, kg , 3 \,kg and 5kg5 \,kg are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force F=10NF=10 \,N, then tension T1=T_{1}=

A

1 N

B

5 N

C

8 N

D

10 N

Answer

8 N

Explanation

Solution

Total mass of the system, M=m1+m2+m3M=m_{1}+m_{2}+m_{3} =2+3+5 =2+3+5 =10kg=10\, kg Force F=10NF=10\, N Hence, acceleration, a=FM=1ms2a=\frac{F}{M}=1 \,ms ^{-2} Now, tension T1T_{1} can be calculated as, T1=(m2+m3)a=8×1=8NT_{1}=\left(m_{2}+m_{3}\right) a=8 \times 1=8\, N