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Question: Three black bodies 1, 2, 3 have radius r<sub>1</sub>\< r<sub>2</sub>\< r<sub>3</sub>. Emissive power...

Three black bodies 1, 2, 3 have radius r1< r2< r3. Emissive powers of black bodies at temperature T are E1, E2, E3. Then correct relation between them is

A

E1< E2< E3

B

E1> E2> E3

C

E1 = E2 = E3

D

E1> E2< E3

Answer

E1 = E2 = E3

Explanation

Solution

Conceptual.