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Question: Thomson coefficient of a conductor is \(10\mu V ⥂ / ⥂ K\). The two ends of it are kept at \(50^{o} ⥂...

Thomson coefficient of a conductor is 10μV⥂/⥂K10\mu V ⥂ / ⥂ K. The two ends of it are kept at 50o⥂C50^{o} ⥂ C and 60o⥂C60^{o} ⥂ C respectively. Amount of heat absorbed by the conductor when a charge of 10C flows through it is

A

1000 J

B

100 J

C

100 mJ

D

1 mJ

Answer

1 mJ

Explanation

Solution

By using H=σQθH = \sigma Q\theta

⇒ H=(10×10−6)×10×(60−50)=10−3J=1mJH = (10 \times 10^{- 6}) \times 10 \times (60 - 50) = 10^{- 3}J = 1mJ