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Question

Mathematics Question on Mean of Grouped Data

Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarised as follows. Find the mean heartbeats per minute for these women, choosing a suitable method.

Number of heartbeats per minute65 - 6868 - 7171 - 7474 - 7777 - 8080 - 8383 - 86
Number of boxs2438742
Answer

To find the class mark (xix_i) for each interval, the following relation is used.

Class mark (xi)(x_i) = Upper limit + Lower limit2\frac {\text{Upper \,limit + Lower \,limit}}{2}

class size (h) of the data = 3

Taking 75.5 as assumed mean (a), did_i, uiu_i, and fiuif_iu_i can be calculated as follows.

**Number of heart beats per minute **Number of women ( fi\bf{f_i}**) **** xi\bf{x_i} **di=xi75.5\bf{d_i = x_i -75.5}ui=di3\bf{u_i = \frac{d_i}{3}}fiui\bf{f_iu_i}
65 - 68266.5-9-3-6
68 - 71469.5-6-2-8
71 -74372.5-3-1-1
74 - 77875.5-3-1-3
77 - 80778.5317
80 - 83778.5317
83 - 86284.5936
**Total **304

From the table, it can be observed that

fi=30\sum f_i = 30
fiui=4\sum f_iu_i = 4

Mean, x=a+(fiuifi)h\overset{-}{x} = a + (\frac{\sum f_iu_i}{\sum f_i})h

x = 75.5+(430)×2075.5 + (\frac{4 }{30}) \times 20

x = 75.5 - (430)×3(\frac{4}{30}) \times 3

x = 75.5 + 0.4

x = 75.9

Therefore, mean hear beats per minute for these women are 75.9 beats per minute.