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Question

Physics Question on electrostatic potential and capacitance

There is an electric field E in x-direction. If the work done on moving a charge of 0.2 C through a distance of 2 m along a line making an angle 60^{\circ} with x-axis is 4 J, then what is the value of E?

A

5 N / C

B

20 N/ C

C

3\sqrt 3 N / C

D

4 N / C

Answer

20 N/ C

Explanation

Solution

Charge (q) = 0.2 C; Distance (d) = 2 m; Angle θ=60\theta = 60^\circ and work done (W) = 4 J.
Work done in moving the charge (W)
= F.dcosθ=qEdcosθ F . d \, cos \, \theta = q E d \, cos \, \theta
or, E = Wqdcosθ=40.2×2×cos60=40.4×0.5 \frac{ W}{ qd \, cos \, \theta } = \frac{ 4}{ 0. 2 \times 2 \times cos \, 60^\circ } = \frac{ 4 }{ 0.4 \times 0. 5}
= 20 N / C.