Question

There is a hole of area A at the bottom of cylindrical vessel. Water is filled up to a height h and water flows out in t second. If water is filled to a height 4h, it will flow out in time equal to

• A. t
• B. 4t
• C. 2 t
• D. t/4

Answer 1

Answer: (C)

2 t

Answer 2

Time required to emptied the tank $t = \frac { A } { A _ { 0 } } \sqrt { \frac { 2 H } { g } }$

⇒ $\frac { t _ { 2 } } { t _ { 1 } } = \sqrt { \frac { H _ { 2 } } { H _ { 1 } } } = \sqrt { \frac { 4 h } { h } } = 2$ $\therefore t _ { 2 } = 2 t$