Question

There is a hole in the bottom of tank having water. If total pressure at bottom is 3 atm (1 atm= 10⁵N/m²) then the velocity of water flowing from hole is

• A. $\sqrt { 400 } \mathrm {~m} / \mathrm { s }$
• B. $\sqrt { 600 } \mathrm {~m} / \mathrm { s }$
• C. $\sqrt { 60 } \mathrm {~m} / \mathrm { s }$
• D. None of these

Answer 1

Answer: (B)

$\sqrt { 600 } \mathrm {~m} / \mathrm { s }$

Answer 2

Pressure at the bottom of tank and

velocity of water $v = \sqrt { 2 g h }$

$\therefore v = \sqrt { \frac { 2 P } { \rho } } = \sqrt { \frac { 2 \times 3 \times 10 ^ { 5 } } { 10 ^ { 3 } } } = \sqrt { 600 } \mathrm {~m} / \mathrm { s }$