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Question

Mathematics Question on Determinant

There are two values of a for which the determinant, Δ=[125\[0.3em]0a1\[0.3em]042a\[0.3em]]=86\Delta =\begin{bmatrix}1& -2& 5\\\[0.3em]0& a& 1\\\[0.3em] 0& 4& 2a\\\[0.3em] \end{bmatrix} = 86, then the sum of these values of a is:

A

41\sqrt{41}

B

0

C

41- \sqrt{41}

D

2412 \sqrt{41}

Answer

0

Explanation

Solution

The correct option is (B): 0