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Question: There are two radio nuclei A and B. A is an alpha emitter and B a beta emitter. Their disintegration...

There are two radio nuclei A and B. A is an alpha emitter and B a beta emitter. Their disintegration constants are in the ratio of 1 : 2. What should be the ratio of number of atoms of A and B at any time t so that probabilities of getting alpha and beta particles are same at that instant –

A

2 : 1

B

1 : 2

C

e

D

1/e

Answer

2 : 1

Explanation

Solution

= 12\frac { 1 } { 2 } Probability of getting ‘a’ and ‘b’ particles are same. Thus rate of disintegration are equal lANA = lBNB

= = 2