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Question

Mathematics Question on Surface Area of Cube, Cuboid and Cylinder

There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?
two cuboidal boxes

Answer

We know that,
Total surface area of the cuboid = 2(lh+bh+lb)2 (lh + bh + lb)
Total surface area of the cube =6(l)26 (l)^ 2
Total surface area of cuboid (a) = [2{(60) (40) + (40) (50) + (50) (60)}] cm2
= [2(2400 + 2000 + 3000)] cm2
= (2×\times 7400) cm2
= 14800 cm2
Total surface area of cube (b) = 6 (50 cm)2 = 15000 cm2
Thus, the cuboidal box (a) will require lesser amount of material.