Question

There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?

Answer 1

We know that,
Total surface area of the cuboid = $2 (lh + bh + lb)$
Total surface area of the cube =$6 (l)^ 2$
Total surface area of cuboid (a) = [2{(60) (40) + (40) (50) + (50) (60)}] cm2
= [2(2400 + 2000 + 3000)] cm2
= (2$\times$ 7400) cm2
= 14800 cm2
Total surface area of cube (b) = 6 (50 cm)2 = 15000 cm2
Thus, the cuboidal box (a) will require lesser amount of material.