Solveeit Logo

Question

Question: There are three passengers on an airport shuttle bus that makes stops at four different hotels. The ...

There are three passengers on an airport shuttle bus that makes stops at four different hotels. The probability that all three passengers will be staying at different hotels, is-
(a) 116\dfrac{1}{{16}}
(b) 14\dfrac{1}{4}
(c) 38\dfrac{3}{8}
(d) 34\dfrac{3}{4}

Explanation

Solution

Hint : Start by mentioning all the given conditions. Then evaluate each and every condition and according to that evaluate the values. After evaluating the values for each condition, put all the terms together and evaluate the final answer.

Complete step by step solution:
First we will start off by mentioning the total number of hotels and the number of passengers.
So, there are a total of 33 passengers and 44 hotels.
Now we will evaluate the number of ways in which the passengers can choose different hotels.
Now, here there are 44 hotels and 33 passengers, also here the decision of choosing the hotel lies totally on the passenger so that will be the deciding factor. So, the total number of ways of choosing 33 hotels among 44 hotels is 4C3{}^4{C_3} but the passengers choosing the hotel can also be rearranged. So, the total number of ways will be given by 4C3×3!{}^4{C_3} \times 3! . If we evaluate its value, it comes out as 2424 .
Now we will evaluate the total number of ways in which a passenger chooses a hotel.
So, a passenger can choose among 44 hotels so the number of ways will be 44 . Now, the next passenger can choose in
3C2×4C1×3C1{}^3{C_2} \times {}^4{C_1} \times {}^3{C_1} and the number of ways for choosing the hotel for the third passenger will be 4C3×3!{}^4{C_3} \times 3! .
Hence, the total number of ways will be
4+3C2×4C1×3C1+4C3×3!4 + {}^3{C_2} \times {}^4{C_1} \times {}^3{C_1} + {}^4{C_3} \times 3! .
Now, if we calculate the value it comes out as 6464
Now, we will evaluate the probability.
P=2464 =38   P = \dfrac{{24}}{{64}} \\\ = \dfrac{3}{8} \;
Hence, the probability that all three passengers will be staying at different hotels is 38\dfrac{3}{8} which is option (C).
So, the correct answer is “Option C”.

Note : While mentioning conditions, make sure to mark all the important words so that you do not miss any important terms. Then next always evaluate all the conditions and then evaluate their values step by step to avoid any confusions. The probability of an event is a number between 0 and 1, where, roughly speaking, 0 indicates impossibility of the event and 1 indicates certainty.