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Question

Mathematics Question on permutations and combinations

There are three coplanar parallel lines. If any PP points are taken on each of the lines, the maximum number of triangles with vertices at these points, is

A

3PC3^{3P}C_{3}

B

P2(P1)P^{2} \left(P-1\right)

C

P2(4P1)P^{2} \left(4P-1\right)

D

P2(4P3)P^{2} \left(4P-3\right)

Answer

P2(4P3)P^{2} \left(4P-3\right)

Explanation

Solution

Required number of ways =PC1×PC1×PC1+PC2×2PC1×3P1=\, ^{P}C_{1} \times\, ^{P}C_{1} \times\,^{P}C_{1} + \,^{P}C_{2} \times\,^{2P}C_{1} \times\, ^{3}P_{1} =P2(4P3) = P^{2}\left(4P-3\right).