Question
Mathematics Question on permutations and combinations
There are three coplanar parallel lines. If any P points are taken on each of the lines, the maximum number of triangles with vertices at these points, is
A
3PC3
B
P2(P−1)
C
P2(4P−1)
D
P2(4P−3)
Answer
P2(4P−3)
Explanation
Solution
Required number of ways =PC1×PC1×PC1+PC2×2PC1×3P1 =P2(4P−3).